A conductivity cell was filled with 0.01 M solution of KCl which was known to have a specific conductivity of 0.1413 `ohm^(-1) m^(-1)` at 298 K. Its measured resistance at 298 K was 94.3 ohm. When the cell was filled with 0.02 M `AgNO_(3)` solution, its resistance was 50.3 ohm. Calculate (i) cell constant and (ii) the specific conductance of `AgNO_(3)` solution.

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

A conductance cell was calibrated by filling it with a 0.02 M solution of potassium chloride (specific conductance = 0.2768 ohm^(-1) m^(-1) ) and measuring the resistance at 298 K which was found to be 457.3 ohm. The cell was then filled with a calcium chloride solution containing 0.555 g of CaCl_(2) per litre. The measured resistance was 1050 ohm. Calculate the molar conductivity of CaCl_(2) solution.

Resistance is 82.3 ohm, when a conductivity cell is filled with 0.02 (N) KCl solution at a definite temperature. At the same temperature, the specific conductance of 0.02 (N) KCl solution is "0.002758 ohm.cm"^(-1) . The resistance is 324 ohm when the cell is filled with :0.05 (N)K_(2)SO_(4) solution. Calculated the equivalent and molar conductivity of K_(2)SO_(4) solution.

A cell with N//50 KCl solution offered a resistance of 550 ohm at 298 K. The specific conductance of N//50 KCl at 298 K is 0.002768 ohm^(-1)cm^(-1) . When this cell is filled with N//10 ZnSO_(4) solution, it offered a resistance of 72.18 ohm at 298 K. Find the cell constant and molar conductance of ZnSO_(4) solution at 298 K.

A conductivity cell has a cell constant of 0.5 cm^(-1) . This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at 25^(@)C . Calculate the equivalent conductance of the given solution.

A conductivity cell has a cell constant of "0.5 cm"^(-1) . This cell when filled with 0.01 M NaCl solution has a resistance of "384 ohm at "25^(@)C . Calculate the equivalent conductance of the given solution.

A conductivity cell has a cell constant of 0.5 cm^(-1) . This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at 25^(@)C . Calculate the equivalent conductance of the given solution.