A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of `2.768xx10^(-3)ohm^(-1)cm^(-1)` . If its resistance is 82.4 ohm at `25^(@)` C the cell constant is:

A conductivity cell has beeen calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance, kappa =1.25xx10^(-3)"S.cm"^(-1) ) in the cell and the measured resistance was 800 ohm at 25^(@)C . The cell constant will be -

A conductivity cell was filled with 0.01 M solution of KCl which was known to have a specific conductivity of 0.1413 ohm^(-1) m^(-1) at 298 K. Its measured resistance at 298 K was 94.3 ohm. When the cell was filled with 0.02 M AgNO_(3) solution, its resistance was 50.3 ohm. Calculate (i) cell constant and (ii) the specific conductance of AgNO_(3) solution.

A conductivity cell has been callibrated with a 0.01 M 1 : 1 electropyte solution (specific conductance, k = 1.25 xx 10^(-3) S cm^(-1) ) in the cell and the measured resistance was 800 ohms at 25^@C . The cell constant will be :

Calculate the cell constant if the specific conductance of a Solution is 0.2 "ohm"^(-1)cm^(-1) and its conductance is 0.04 "ohm"^(-1) .

Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is 1.33xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is

Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is .133xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is