Let `f(theta)=1/(tan^2theta){(1+tantheta)^3+(2+tantheta)^3+......+(10+tan theta)^3}-10 tan theta` Then, `lim_(theta->pi/2)f(theta)` is equal to

Let f(theta)=(1)/(tan^(2)theta){(1+tan theta)^(3)+(2+tan theta)^(3)+......+(10+tan theta)^(3)}-10tan theta Then,lim_(theta rarr(pi)/(2))f(theta) is equal to

Let f(theta)=(1)/(tan^9 theta){(1+tantheta)^10+(2+tantheta)^10+....+(20+tantheta)^10}-20tan theta The left hand limit of f(theta)" as "theta to (pi)/(2) ,is

tan 3theta = tan 2theta + tantheta

tan3theta + tantheta = 2tan 2theta

sin^(3)theta = tan2theta + tantheta

theta=tan^-1(2tan^2theta)-tan^-1{(1/3)tantheta} , if

theta=tan^(-1)(2tan^(2)theta)-tan^(-1)(1/3tantheta) if

Prove that (tan^3theta-1)/(tantheta-1)=sec^2theta+tantheta .

tantheta+tan(6 0^0+theta)+tan(12 0^0+theta)=3tan3theta

tantheta+tan(6 0^0+theta)+tan(12 0^0+theta)=3tan3theta