There are two points `A (a, 0) and B (-a, 0)` . If `/_A-/_B=theta` then the locus of C in the triangle ABC is

The vertices of a triangle ABC are the points (0, b), (-a, 0), (a, 0) . Find the locus of a point P which moves inside the triangle such that the product of perpendiculars from P to AB and AC is equal to the square of the perpendicular to BC .

Given two points A and B. If area of triangle ABC is constant then locus of point C in space is

Given two points A and B. If area of triangle ABC is constant then locus of point C in space is

Given two points A and B. If area of triangle ABC is constant then locus of point C in space is

If theta is parameter, A=(a cos theta,a sin theta) and B=(b sin theta,-b cos theta)C=(1,0) then the locus of the centroid of Delta ABC

Let A=(4, 0), B=(0, 12) be two points in the plane. The locus of a point C such that the area of triangle ABC is 18 sq. units is -

In a triangle ABC,2/_A=3/_B=6/_C. Then the smallest angle in the Delta ABC is

A(2, 5), B(4, -11) are two fixed points and C is a point which moves on the line 3x+4y+5=0 . Find the locus of the centroid of the triangle ABC.

If sin theta and -cos theta are the roots of the equation ax^(2) - bx - c = 0 , where a, b, and c are the sides of a triangle ABC, then cos B is equal to