The horizontal component of the earth's magnetic field is `3.6 xx 10^(-5) T` where the dip is `60^@`. Find the magnitude of the earth's magnetic field.

The horizontal component of earths's magnetic field at a place is 0.3 xx 10^-4T . If the angle of dip is 60^@ , what is the total earth's magnetic field?

The horizontal component of the earth's magnetic field at a certain place is 2.6 xx 10^(-5) T and the angle of dip is 60^(@) . What is the magnetic field of the earth at this location ?

The horizontal component of earth's magnetic field is 3 xx 10^(-4) T. The magnetic dip angle is 45°. Find the vertical component.

In the magnetic meridian of a certain place, the horizontal component of earth's magnetic fied is 0.26 G and the dip angle is 60^@ . Find a. Vertical component of earth's magnetic field b. the net magnetic field at this place

In the magnetic meridian of a certain place, the horizontal component of earth's magnetic fied is 0.26 G and the dip angle is 60^@ . Find Vertical component of earth's magnetic field b. the net magnetic field at this place

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26 G and the dip angle is 60^@ . What is the magnetic field of the earth at this location ?

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26 G and the dip angle is 60^(@) . What is the magnetic field of the earth at this location ?

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^@ . What is the value of horizontal component of earth's magnetic field at equator?