Use product `[1-1 2 0 2-3 3-2 4][-2 0 1 9 2-3 6 1-2]`to solve the system of equations`x-y + 2z= 1``2y-3z= 1``3x-2y + 4z = 2`

Explanation

given matrix are `[1-1 2 0 2-3 3-2 4][-2 0 1 9 2-3 6 1-2]`

thus, multiply both of them

`[1 0 0 0 1 0 0 0 1]`

Now, `AB=I`

thus, `A^-1=B`

`A^-1=[-2 0 1 9 2-3 6 1-2]`


From system of equation, we can say that, AX=C

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