PORS is a parallelogram and x and Y trisect side OR. Show that `ar (triangle POX)` is equal to `ar (triangle SRY)`

In the adjoining figure, ABCD is a parallelogram. Points P and Q on BC trisect BC. Prove that ar(triangleAPQ)=ar(triangleDPQ)=(1)/(6)ar(triangleABCD) .

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that ar (Delta AXS) = (1)/(2) ar (PQRS)

PQRS and ABRS are parallelograms and X is any point on the sides BR. Show that ar(PQRS)=ar(ABRS)

In, PQRS and ABRS are parallelograms and X is any point on side BR. Show that ar (PQRS) = ar (ABRS) as (AXS) = (1)/(2) ar (PQRS)

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that (i) ar(PQRS) = ar(ABRS) (ii) ar(DeltaAXS) =1/2 ar(PQRS)

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that (i) ar(PQRS) = ar(ABRS) (ii) ar(DeltaAXS) =1/2 ar(PQRS)

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that (i) ar(PQRS) = ar(ABRS) (ii) ar(DeltaAXS) =1/2 ar(PQRS)

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that (i) ar(PQRS) = ar(ABRS) (ii) ar(DeltaAXS) =1/2 ar(PQRS)

In the figure, PQRS and ABRS are parallelograms and X is any point on side BR. Show that ar(PQRS) = ar(ABRS)

In Fig.9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar(PQRS)=ar(ABRS) (ii) ar (AXS)backslash=(1)/(2)ar(PQRS)