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If the velocity of a particle is v = At ...

If the velocity of a particle is `v = At + Bt^2`, where `A` and `B` are constant, then the distance travelled by it between `1 s` and `2 s` is :

A

`3A+7B`

B

`(3)/(2)A+(7)/(3)B`

C

`(A)/(2) + (B)/(3)`

D

`(3)/(2)A+4B`

Text Solution

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The correct Answer is:
B
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