A uniform force of (3hati+hatj) N acts o...

A uniform force of `(3hati+hatj)` N acts on a particle of mass 2kg. Hence, the particle is displaced from position `(2hati+hatk)`m to position `(4hati+3hatj-hatk)`m. The work done by the force on the particle is

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A uniform force of (3 hati + hatj) newton acts on a partical of mass 2 kg . Hence the partical is displaced from position (2 hati + hatk) metre to possion (4 hati + 3 hatj - hatk) meters. The work done by the force on the partical is

A uniform force of (5hati +5hatj)N acts on particle of mass 1 kg. The particle moves from r_1 = (3hati + 4hatj)m to r_2 = (5hati + 8hatj) m under this force. The work done by this force is

A constant force vecF=(3hati+2hatj+2hatk) N acts on a particle displacing it from a position vec(r_1)=(-hati+hatj-2hatk)m to a new position vecr_2=(hati-hatj+3hatk)m . Find the work done by the force.

Under a force ( 10 hati - 3 hatj + 6 hatk) newton a body of mass 5 kg moves from position ( 6 hati + 5 hatj - 3 hatk) m to position ( 10 hati - 2hatj+ 7hatk) m . Deduce the work done.

Under the effect of a force vecF=5hati-2 hatj+3hatk N, abody of mass 1 kg is displaced from position 5hati+4hatj-2hatk to position 8hati-hatj-hat4k . Calculate the work done .

Under a force of 10 hati - 3 hatj +6 hatk newton, a body of mass 5 kg is displaced from the position 6 hati + 5 hatj - 3 hatk to the position 10 hati - 2hatj + 7 hatk . Calculate the work done.

A particle acted upon by constant forces 4hati +hatj- 4 hatk and 3hati + hatj - hatk is displacment from the point hati+ 2hatj+ hatk to point 5hati + 4hatj +hatk .Total work done by the forces in SI unit is :

Under a fore (10hati-3hatj+6hatk) newton a bod of mass 5 kg moves from position (6hati+5hatj-3hatk) m to position (10hati-2hatj+7hatk) m. deduce the work done.

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