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Two bodies with kinetic energies in the ratio 4:1 are moving with equal linear momentum. The ratio of their masses is

A

`1:2`

B

`1:1`

C

`4:1`

D

`1:4`

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The correct Answer is:
To solve the problem, we need to find the ratio of the masses of two bodies that have kinetic energies in the ratio of 4:1 and are moving with equal linear momentum. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy and Momentum**: - The kinetic energy (KE) of an object is given by the formula: \[ KE = \frac{p^2}{2m} \] where \( p \) is the linear momentum and \( m \) is the mass of the object. - Since both bodies have equal linear momentum, we can denote their momenta as \( p \). 2. **Setting Up the Ratios**: - Let the kinetic energies of the two bodies be \( KE_1 \) and \( KE_2 \). - According to the problem, the ratio of their kinetic energies is: \[ \frac{KE_1}{KE_2} = \frac{4}{1} \] 3. **Expressing Kinetic Energies in Terms of Mass**: - For the first body: \[ KE_1 = \frac{p^2}{2m_1} \] - For the second body: \[ KE_2 = \frac{p^2}{2m_2} \] 4. **Setting Up the Equation**: - Now, substituting the expressions for kinetic energies into the ratio: \[ \frac{KE_1}{KE_2} = \frac{\frac{p^2}{2m_1}}{\frac{p^2}{2m_2}} = \frac{m_2}{m_1} \] - Since \( p^2 \) and \( 2 \) are common in both the numerator and denominator, they cancel out. 5. **Using the Given Ratio**: - We know from the problem that: \[ \frac{KE_1}{KE_2} = \frac{4}{1} \] - Therefore, we can equate this to our previous expression: \[ \frac{m_2}{m_1} = \frac{4}{1} \] 6. **Finding the Mass Ratio**: - Rearranging gives us: \[ \frac{m_1}{m_2} = \frac{1}{4} \] - Thus, the ratio of the masses \( m_1:m_2 \) is: \[ m_1:m_2 = 1:4 \] ### Final Answer: The ratio of their masses is \( 1:4 \).
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