Point masses `m_(1) and m_(2)` are placed at the opposite ends of a rigid rod of length `L`, and negligible mass. The rod is to be set rotating about an axis perpendicualr to it. The position of point `P` on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity `omega_(0)` is minimum, is given by :

Options

A. `x= (m_(1)L)/(m_(1)+m_(2))`
B. `x= m_(1)/m_(2) L`
C. `x= m_(2)/m_(1) L`
D. `x= (m_(2)L)/(m_(1)+m_(2))`

Answer

d