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A circular disc of moment of inertia I(t...

A circular disc of moment of inertia `I_(t)` is rotating in a horizontal plane about its symmetry axis with a constant angular velocity `omega_(i)`. Another disc of moment of inertia `I_(b)` is dropped co-axially onto the rotating disc. Initially, the second disc has zero angular speed. Eventually, both the discs rotate with a constant angular speed `omega_(f)`. Calculate the energy lost by the initially rotating disc due to friction.

A

`1/2 I_(b)^(2)/((I_(t)+I_(b))) omega_(i)^(2)`

B

`1/2 I_(t)^(2)/((I_(t)+I_(b))) omega_(i)^(2)`

C

`1/2 (I_(b)-I_(t))/((I_(t)+I_(b))) omega_(i)^(2)`

D

`1/2 (I_(b) I_(t))/((I_(t)+I_(b))) omega_(i)^(2)`

Text Solution

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The correct Answer is:
d
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