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A particle is executing a simple harmoni...

A particle is executing a simple harmonic motion. Its maximum acceleration is `alpha` and maximum velocity is `beta`. Then, its time period of vibration will be

A

`(beta^(2))/(alpha^(2))`

B

`(alpha)/(beta)`

C

`(beta^(2))/(alpha)`

D

`(2 pi beta)/(alpha)`

Text Solution

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The correct Answer is:
D
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