A mass is suspended separately by two springs of spring constants `k_(1)` and `k_(2)` in successive order. The time periods of oscillations in the two cases are `T_(1)` and `T_(2)` respectively. If the same mass be suspended by connecting the two springs in parallel, (as shown in figure) then the time period of oscillations is T. The correct relations is

Options

A. `T^(2) = T_(1)^(2) + T_(2)^(2)`
B. `T^(-2) = T_(1)^(-2) + T_(2)^(-2)`
C. `T^(-1) = T_(1)^(-1) + T_(2)^(-1)`
D. `T = T_(1)+T_(2)`

Answer

B