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In a ` A B C ,A-=(alpha,beta),B-=(1,2),C-=(2,3),` point `A` lies on the line `y=2x+3,` where `alpha,beta` are integers, and the area of the triangle is `S` such that `[S]=2` where `[` .`]` denotes the greatest integer function. Then the possible coordinates of `A` can be `(-7,-11)` (b) `(-6,-9)` `(2,7)` (d) `(3,9)`

A

`a-b=7`

B

`a+b=5`

C

minimum value of the quadratic expression whose zero's are `a` and `b` and leading coefficient is `4` is`-49`

D

minimum value of the quadratic expession whose zero's are `a` and `b` and leading coefficient is `-1` is`49/4`

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Verified by Experts

The correct Answer is:
A, B, C, D

Slope of `AC=(9-3)/(3-2)=6`
Equation of `AC` is`y-3=6(x-2)`
`implies6x-y=9`
But we have equation of `AC` is `ax+by=9`
`impliesa=6,b=-1impliesa+b=5`
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