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CH(3)-underset(CH(3)) underset(|) (C)= C...

`CH_(3)-underset(CH_(3)) underset(|) (C)= CH_(2) underset("Peroxide") overset(HBr)to CH_(3)-underset(CH_(3)) underset(|) (CH)-CH_(2)Br` reaction intermediate of this reaction is:

A

`CH_(3)-underset(CH_(3))underset(|) overset(dot) (C)-CH_(2)Br`

B

`CH_(3)-underset (CH_(3))underset(|)(CH)-overset(dot)(C)H_(2)`

C

`CH_(3)-underset(CH_(3)) underset(|)overset(dot)(C)-CH_(3)`

D

`CH_(3)-underset(CH_(3)) underset(|) overset(Br) overset(|) (C)- overset(.) (C)H_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`R-O-OR overset(hv)(rarr)RO^(dot)`
`RO^(dot)+HBrrarrROH+Br^(dot)`
`CH_(3)-C(CH_(3))=CH_(2)+Br^(dot)rarrCH_(3)-underset(CH_(3)) underset(|) overset(dot) (C)-CH_(2)Br` is more stable intermediate.
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