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Let P and Q be two statements, then ~(~P...

Let P and Q be two statements, then `~(~P^^Q)^^(PvvQ)` is logically equivalent to

A

`Q`

B

`P`

C

`PvvQ`

D

`P^^Q`

Text Solution

Verified by Experts

The correct Answer is:
B

`~(~P^^Q)^^(PvvQ)=[~(~P)vv(~Q)]^^(PvvQ)`
`[Pvv(~Q)^^(PvvQ)]`
`=Pvv[(~Q)^^Q]`
`=PvvF=P`
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