Home
Class 11
PHYSICS
A cubical block of wood of 10cm and mass...

A cubical block of wood of `10cm` and mass `0.92kg` floats on a tank of water with oil or rel. density `0.6`. Thickness of oil is `4cm` above water. When the block attains equilibrium with four of its sides edges verical:

A

`1 cm` of it will be above the free surface of oil.

B

`5 cm` of it will be under water.

C

`2 cm` of it will be above the common surface of oil and water.

D

`8 cm` of it will be under water.

Text Solution

Verified by Experts

The correct Answer is:
C, D
Assuming that the block is completely submerged in water, then
`F_(b) = 1000 gt mg(920)` So, not possible
Let complete in oil
`F_(b) = (0.6)(4)(1000 + (1)(6)(100) = 840`
`F_(b) lt mg` So, not possible
So, let `'x'` part in oil and remaining in water
`920 = [(1)(10 - x) + (0.6)(x)] 100`
`9.2 = 10 - x + 0.6 x`
`0.4 x = 0.8`
`x = 2 cm`.
Promotional Banner

Topper's Solved these Questions

  • FLUID MECHANICS

    RESONANCE|Exercise Exercise- 2 PART - IV|10 Videos

  • FLUID MECHANICS

    RESONANCE|Exercise Exercise- 3 PART - I|17 Videos

  • FLUID MECHANICS

    RESONANCE|Exercise Exercise- 2 PART - II|9 Videos

  • ELECTROSTATICS

    RESONANCE|Exercise Exercise|52 Videos

  • FULL TEST 1

    RESONANCE|Exercise Exercise|30 Videos

Similar Questions

Explore conceptually related problems

A cubical block of wood having an edge 10 cm and mass 0.92 kg floats on a tank of water with oil of relative density 0.5 to a height of 4 cm above water. When the block attains equilibrium with four of its edges vertical

A cubical box of wood of side 30 cm and mass 21.6 kg floats on water with two faces horizontal. The length of immersed part in water is : (rho_("wood")=0.8g//c c)

A cubical block of wood 10 cm on a side, floats at the interface of oil and water as shown in figure. The density of oil is 0.6 g cm^(-3) and density of water is 1 g cm^(-3) . The mass of the block is

A piece of wood of relative density 0.25 floats in a pail containing oil of relative density 0.81. What is the fraction of volume of the wood above the surface of the oil ?

A cubical box of wood of side 30 cm weighting 21.6 kg floats on water with two faces horizontal. Calculate the depth of immersion of wood.

A block of wood floats in water with 2/3 of its volume submerged. Its relative density is

A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is 0.6 gcm^(-3) . The mass of block is

A cubical block of wood 10cm on a side floats at the interface between oil and water, as in fig. with its lower face 2 cm below the interface. The intensity of the oli is 0.6 g cm^(-3) . The mass of the block is

A cubical block is initially on water such that its (4)/(5)th volume is submersed in water. Now oil is poured on water and when block attains equilibrium its half volume is in water and half volume is in oil. The relative density of oil is:

The densit of a block of wood which flots on water with 0.1 of its volume above water is: