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When the load on a wire increased slowly...

When the load on a wire increased slowly from `2 kg wt.` to `4 kg wt.`, the elogation increases from `0.6 mm` to `1.00 mm`. How much work is done during the extension of the wire? `[ g = 9.8 m//s^(2)]`

Text Solution

Verified by Experts

The correct Answer is:
`13.72 xx 10^(-3)J`.
`W = (1)/(2)(F_(2)x_(2) = F_(1)x_(1))`
`= (1)/(2) (4 xx 9.8 xx 10^(-3) - 2 xx 9.8 xx 0.6 xx 10^(-3))`
`= 2 xx 9.8 xx 10^(-3) xx 0.7 = 13.72 xx 10^(-3)J`
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