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if a ball of steel (density rho=7.8 g//c...

if a ball of steel (density `rho=7.8 g//cm^(3)`) attains a terminal velocity of `10 cm//s` when falling in a tank of water (coefficient of viscosity, `eta_(water) =8.5xx10^(-4)`Ps s), then its terminal velocity in glycerine `(rho =1.2 g//cm^(2), eta =13.2 Pa s)` would be nearly

A

`6.25 xx 10^(-4)cms^(-1)`

B

`6.45 xx 10^(-4) cms^(-1)`

C

`1.5 xx 10^(-5) cm//s`

D

`1.6 xx 10^(-5) cms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`V_rhog = 6pietarv + vrho_(l)g`
`Vg(rho - rho_(l)) = 6pietarv`
`Vg(rho - rho_(l)) = 6pieta'rv'`
`V'eta' = ((rho - rho_(l)'))/((rho - rho_(l))) xx (veta)/(eta')`
`= ((7.8 xx 1.2))/((7.8 - 1)) xx (10 xx 8.5 xx 10^(-4))/(13.2)`
`v' = 6.25 xx 10^(-4) cm//s`.
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