[15.,2ax+3by=a+2b],[" CERT ",3ax+2by=2a+b]

Solve the following system of equations by method of cross-multiplication: 2ax+3by=a+2b,quad 3ax+2by=2a+b

(ax)/b-(by)/a=a+b , ax-by=2ab

(ax)/(b)-(by)/(a)=a+b,ax-by=2ab

If A=[[1, 2, 3], [-1, 1, 2], [1, 2, 4]], B=[[1], [2], [3]] and AX=B , then X=

If the derivative of the function f(x) is every where continuous and is given by f(x)={{:(bx^(2)+ax+4,,, x ge 1), (ax^(2)+b, ,, x lt -1):}, then : a)a = 2, b = -3 b)a = 3, b = 2 c)a = -2, b = -3 d)a = -3, b= -2

{:(x + y = a + b),(ax - by = a^(2) - b^(2)):}

If the arithmetic mean of the numbers x_1, x_2, x_3, ..., x_n is barx, then the arithmetic mean of the numbers ax_1 +b, ax_2 +b, ax_3 +b, ....,ax_n +b, where a, b are two constants, would be

If the arithmetic mean of the numbers x_1 , x_2, x_3,……., x_n is barx , then the arithmetic mean of the numbers ax_1 + b, ax_2 + b, ax_3 + b, ……, ax_n + b , where a and b are two constants, would be:

If the arithmetic mean of the numbers x_1, x_2, x_3, ..., x_n is barx, then the arithmetic mean of the numbers ax_1 +b, ax_2 +b, ax_3 +b, ....,ax_n +b, where a, b are two constants, would be

If the arithmetic mean of the numbers x_1, x_2, x_3, ..., x_n is barx, then the arithmetic mean of the numbers ax_1 +b, ax_2 +b, ax_3 +b, ....,ax_n +b, where a, b are two constants, would be