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1+ pr I py 1+ pz' Z) (z -x)...

1+ pr I py 1+ pz' Z) (z -x)

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1+ pr I py 1+pz'Z)(zx)

{:|( x,x^(2) , 1+ px^(3) ),( y,y^(2) , 1+ py^(2)),( z,z^(2) , 1+pz^(2)) |:} =( 1+pxyz ) ( x-y) ( y-z ) (z-x) , where p is any scalar .

using properties of determinant prove that {:[( x,x^(2) , 1+ px^(3) ),( y,y^(2) , 1+ py^(2)),( z,z^(2) , 1+pz^(2)) ]:} =( 1+pxyz ) ( x-y) ( y-z ) (z-x) , where p is any scalar .

{:[( x,x^(2) , 1+ px^(3) ),( y,y^(2) , 1+ py^(3)),( z,z^(2) , 1+pz^(3)) ]:} =( 1+pxyz ) ( x-y) ( y-z ) (z-x) , where p is any scalar .

Nitrogen has the electronic configuration '1 s^2 2 s^2 p_x^1 2 p_y^1 2 p_z^1' and not '1 s^2 2 s^2 2 p_x^2 2 p_y^1 2 p_z^0' which is determined by