The electronic configuration of an element is `1s^(2),2s^(2)2p^(6),3s^(1),3p^(3)3d^(2)`. The atomic number of the element present just below this element in the periodic table-

Options

A. 36
B. 34
C. 33
D. 32

Explanation

To find the atomic number of the element that is present just below the given element in the periodic table, we first need to analyze the provided electronic configuration.

### Step-by-Step Solution:

1. **Identify the Given Electronic Configuration**:
The electronic configuration provided is \(1s^2, 2s^2, 2p^6, 3s^1, 3p^3, 3d^2\).

2. **Count the Total Number of Electrons**:
- \(1s^2\): 2 electrons
- \(2s^2\): 2 electrons
- \(2p^6\): 6 electrons
- \(3s^1\): 1 electron
- \(3p^3\): 3 electrons
- \(3d^2\): 2 electrons

Now, add these together:
\[ 2 + 2 + 6 + 1 + 3 + 2 = 16 \]
Therefore, the atomic number of the element is 16.

3. **Identify the Element**:
The element with atomic number 16 is Sulfur (S).

4. **Locate the Element Below Sulfur in the Periodic Table**:
In the periodic table, the elements are arranged in groups and periods. Sulfur is located in period 3. The element directly below sulfur in period 4 is Selenium (Se).

5. **Determine the Atomic Number of Selenium**:
Selenium has an atomic number of 34.

### Final Answer:
The atomic number of the element present just below the given element in the periodic table is **34**.

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