If there were 10 periods in the periodic table then how many elements would this period can maximum comprise of

Options

A. 50
B. 72
C. 32
D. 98

Explanation

To determine the maximum number of elements that can be present in the 10th period of the periodic table, we can use the following steps:

### Step-by-Step Solution:

1. **Understanding the Periods**: The periodic table is organized into periods, which correspond to the principal quantum number (n). Each period can accommodate a certain number of elements based on the value of n.

2. **Formula for Maximum Elements**:
- For even values of n (like n = 10), the maximum number of elements in that period can be calculated using the formula:
\[ \text{Maximum Elements} = 2 \times \left( n + 2 \right) \div 2^2 \]
- For odd values of n, the formula is:
\[ \text{Maximum Elements} = 2 \times \left( n + 1 \right) \div 2^2 \]

3. **Applying the Formula for n = 10**:
- Since 10 is an even number, we use the first formula:
\[ \text{Maximum Elements} = 2 \times \left( 10 + 2 \right) \div 2^2 \]
- Simplifying this:
\[ = 2 \times 12 \div 4 \]
\[ = 24 \div 4 \]
\[ = 6 \]

4. **Calculating the Total Number of Electrons**:
- The total number of electrons that can fit in the nth period is calculated as:
\[ \text{Total Electrons} = 2 \times n^2 \]
- For n = 10:
\[ \text{Total Electrons} = 2 \times 10^2 = 2 \times 100 = 200 \]

5. **Conclusion**:
- Therefore, the maximum number of elements that can be present in the 10th period is **72**.

### Final Answer:
The maximum number of elements that the 10th period can comprise is **72**.