Nature of bond can be predicted on the basis of electronativity of bonded atoms, greater difference in electronegativity (X), more will be the polarity of bond, and polar bond are easily broken in polar solvent like water. For hydroxy acids `X_(0) - X_(A)` difference predict the nature of oxide formed by the element A.
`|X_(0) - X_(A)| gt |X_(0) - X_(H)|` then `A-O-H` show basic nature `(NaOH)`
`|X_(0) - X_(A)| lt |X_(0) - X_(H)|` then `A-O-H` show acidic nature `(H-O-CI)`
With the help of EN values `[EN_(A) = 1.8, EN_(B) = 2.6, EN_(C) = 1.6, EN_(D) = 2.8]` answer the following questions for the compounds `HAO, HBO, HCO, HDO`.
Compounds whose aqueous solution is acidic and order of their acidic strength

Options

A. `AOH, COH , AOH lt COH`
B. `HDO, HBO , HDO gt HBO`
C. `AOH, COH , AOH gt COH`
D. `HDO, HBO , HDO lt HBO`

Answer

B

Explanation

[In a aqueous solution polar bond is breaks first Acidic strength `HDO gt HBO`]