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Pauling give method to calculate univale...

Pauling give method to calculate univalent ion radii by assuming that
(i) In ionic crystal (let `M^(+)X^(-))` cations and anions are is contact of eac other and sum of their radii is equal to interionic distance, i.e.,
`d_((M^(+)-X^(-)) = r_(M^(+) +r_(X^(-))`
(ii) The radius of an ion having noble gas configuration is inversely proportional to the effective nuclear charge felt at the periphery of the ion, i.e., `r_((M^(+))) = (C)/(Z_(eff(M^(+))))` and `r_((X^(-))) = (C)/(Z_(eff(X^(-))))`
Here C is constant of proportionality whose value depends on electronic configuration of ion. Thus,
`d_((M^(+)-X^(-))) =(C)/(Z_(eff(M^(+)))) +(C)/(Z_(eff(X^(-))))` pm
`Z_(eff)` is the effective nuclear charge whose value can be calculated by the formula: `Z_(eff) = Z - sigma`. Here `sigma` is shielding constant and for neon, the value of `sigma` when calculate by Slater's rule is found to be 4.5
The value of univalent radii for `F^(-)` as calculated by Pauling method is (given that interionic distance of `NaF = 231`pm):

A

`94.5` pm

B

`136.5` pm

C

`111.68` pm

D

`115.5` pm

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The correct Answer is:
B
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Pauling give method to calculate univalent ion radii by assuming that (i) In ionic crystal (let M^(+)X^(-)) cations and anions are is contact of eac other and sum of their radii is equal to interionic distance, i.e., d_((M^(+)-X^(-))) = r_(M^(+) +r_(X^(-)) (ii) The radius of an ion having noble gas configuration is inversely proportional to the effective nuclear charge felt at the periphery of the ion, i.e., r_((M^(+))) = (C)/(Z_(eff(M^(+)))) and r_((X^(-))) = (C)/(Z_(eff(X^(-)))) Here C is constant of proportionality whose value depends on electronic configuration of ion. Thus, d_((M^(+)-X^(-))) =(C)/(Z_(eff(M^(+)))) +(C)/(Z_(eff(X^(-)))) pm Z_(eff) is the effective nuclear charge whose value can be calculated by the formula: Z_(eff) = Z - sigma . Here sigma is shielding constant and for neon, the value of sigma when calculate by Slater's rule is found to be 4.5 The value of 'C' for Na^(+), Mg^(2+) and Al^(3+) will be in the order:

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BANSAL-PERIODIC TABLE-EXERCISE-2
  1. Nature of bond can be predicted on the basis of electronativity of bon...

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  2. Pauling give method to calculate univalent ion radii by assuming that ...

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  3. Pauling give method to calculate univalent ion radii by assuming that ...

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  4. Pauling give method to calculate univalent ion radii by assuming that ...

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  5. Statement-I : Ca^(2+) and Sc^(3+) are isolectronic but ionic radius of...

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  6. Statement-I : O rarr O^(2-) is associated with energy absorbed but yet...

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  7. Assertion (A) : EA of O is less than that of F but greater than that o...

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  8. Statement-I : Cs and F combines violently to form CsF. Statement-II :...

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  9. Statement-I : Lithium is a better reducing agent than Cs. Statement-...

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  10. Statement-I : IE(3) of Mn is more than IE(3) of Fe. Statement-II : ...

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  11. Statement-I : Fluorine shows maximum oxidising property in a periodic ...

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  12. Statement-I : The ionisation potential of Sn is greater than Pb. Sta...

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  13. Statement-I : (I.E.)(n) of an atom is always greater than (I.E.)(n-1) ...

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  14. Statement-I : Nitrogen atom has higher ionization energy than fluorine...

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  15. Which of the following is correct order of EA.

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  16. If Hund's rule is not followed and energy of orbitals is governed by"n...

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  17. Amongst the following statements, which is/are correct?

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  18. The ionic compound A^(+)B^(-) is formed when the

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  19. Which of the following is/are correct?

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  20. Which of the following is false

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