The `Pt-CI` distance is `2.32 A` in several crystaline compounds
What is the `CI-CI` distance in structure (i) and in structure (ii)
.

Answer

`[4.64 Å; b = 3.28Å]`

Explanation

`[[Pt (NH_(3))_(2) CI_(2)]` is an square planar complex
(a) `2Pt - Cl - Cl`
`2 xx 2.32 = 4.64 Å`
(b)
`x^(2) = sqrt((2.32)^() +(2.32)^(2)) = 3.28 Å`]