A mixture contains `F` and `Cl` atoms . The removal of an electron form each atom of the sample requires `28 kJ` while addition of an electron to each atom of mixture releases `68.8 kJ` energy .Calcualte the % composition of mixture .Given `IE` per atoms for `F` and `Cl` are `27.91 xx10^(-22)kJ` and `20.77 xx10^(-22) kJ`.
Electron gain enthaply for F and Cl are ` -5. 31 xx10 ^(-22) kJ` and `-5.78 xx 10^(22) kJ` respectivley

Answer

`[F = 37.81%, Cl = 62.19%]`

Explanation

[A mixture contains x and y atoms of F & CI respectively
`27.91 xx 10^(-22) x + 20.77 xx 10^(-22) y = 284`
`5.53 xx 10^(-22) x+ 5.78 xx 10^(-22) y = 68.8]`