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Calculate the electron affinity of iodin...

Calculate the electron affinity of iodine with the help of the following data (given in `Kcal//"mole")`.
`(DeltaH_("for"))_(Nal) =- 68.8, (DeltaH_("sub"))_(Na) = 25.9, (1)/(2) (DeltaH_("sub")+DeltaH_("diss"))_(I_(2)) = 25.5, (IP)_(Na) = 118.4, (U)_(Nal) = - 165.4`

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The correct Answer is:
`[+73.2 kcal//"mole"]`
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