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What is the maximum number of electron p...

What is the maximum number of electron possible in `Ni^(+)` having same spin.

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The correct Answer is:
[0015]
`[Ni^(+) = 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(7)`
Maximum number of electron having same spin `= 15]`
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BANSAL-PERIODIC TABLE-EXERCISE-3
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