`PbF_(4),PbCl_(4)` exist but `PbBr_(4)` and `Pbl_(4)` do not exist because of -

Options

A. Large size of `Br^(-)` and `I^(-)`
B. Strong oxidising character of `Pb^(4+)`
C. Strong reducing character of I and Br
D. low electronegativity og `Br^(-)` and `I^(-)`

Answer

C

Explanation

Due to inert pair effect `Pb^(+2)` is more stable than `Pb^(+4)` but F & Cl act as a oxidant so `PbF_(4)` & `PbCl_(4)` exist. I & Br act as a reducing agent so `PbBr_(4)` and `Pbl_(4)` do not exist.