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Find the position of centre of mass for a system of particles places at the vertices of a regular hexagon as shown in figure

Text Solution

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`x_(cm)=(Sigmam_(i)x_(i))/(Sigmam_(i))`
`=(mxx0+2mxx(a)/(2)+mxx(3a)/(2)+2mxx2a+mxx(3a)/(2)+2mxx(a)/(2))/(m+2m+m+2m+m+2m)`
`x_(cm)=a`
`y_(cm)(Sigmam_(i)y_(i))/(Sigmam_(i))`
`=(mxx0+2mxx(asqrt3)/(2)+mxx(asqrt3)/(2)+2mxx0+mxx((-asqrt3)/(2))+2mxx((-asqrt3)/(2)))/(9m)`
`y_(cm)=0`
`c.m : (a,0)`
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Knowledge Check

  • The position of centre of mass of a system of particles does not depend upon

    A
    masses of particles
    B
    forces on particles
    C
    position of the particles
    D
    relative distance between the particles
  • The position of centre of mass of system of particles at any moment does not depend on

    A
    masses of the particles
    B
    forces on the particles
    C
    positions of the particles
    D
    relative distance between the particles
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