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A railroad flatcar of mass M can roll wi...

A railroad flatcar of mass `M` can roll without friction along a straight horizontal track. Initially, a man of mass 'm' is standing on the car, which is at rest. What is the velocity of the car if man runs to the left so that his speed relative to the car is `v_(rel)`.

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Let velocity of man w.r.t. ground be `V_(m)` and the velocity attained by car be `v_(0)` in backward direction.
`V_(rel)=v_(m)-(-v_(0))` (considering left to be positive)
`v_(m)=v_(rel)-v_(0)`

Applying conservation of momentum in x-direction,
`mv_(m)+M(-v_(0))=0`
`m(v_(rel)-v_(0))-Mv_(0)=0`
`therefore" "v_(0)=(mv_(rel))/(m+M)`
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