The figure shows the positions and velocity of two particle. If the particle move under the mutual attraction of each other, then the position of centre of mass at `t = 1 s` is :-

Answer

`x=6m`

Explanation

`x_(CM)=(1(2)+1(8))/(1+1)=5`
`v_(CM)=(1(5)+1(-3))/(1+1)=1`
`a_(CM)0`[There is no external force on the system]
`s=ut+(1)/(2)at^(2)`
`rArrx_(t=1)-5=(1)(1)+(1)/(2)(0)(1)^(2)" "rArr" "x_(CM)=6`