A smooth sphere `A` of mass `0.1kg` is moving with speed `5m//s` when it collides head on with another smooth stationary sphere `B`.If `A` is brought to rest by the impact and `e=1//2`, find the mass of `B`, its speed just after impact and magnitude of impulse during collision.

Answer

`0.2kg,2.5m//s,0.5Ns`

Explanation

`e=(1)/(2)=(v-0)/(5-0)" "rArr" "v=(5)/(2)=2.5m//s`
Using conservation of momentum `=(0.1)5+M(0)=(0.1)0+M(2.5)`
`rArr0.5=2.5M`
`rArrM=(1)/(5)kg=0.2kg`
Ipulse=change in momentum
`=(0.1)(5.0)=0.5Ns`