Two bolcks `A` & `B` are connected by a spring of stiffness `512N//m` and placed on a smooth horizontal surface. Initially the spring has its equilibrium length. The indicated velocities are imparted to `A` & `B`. Find the maximum extension in the spring?

Answer

25m

Explanation

Using centre of mass frome of refrence, we can say that
`(1)/(2)muv_(rel)^(2)=(1)/(2)kx^(2)` [Here `mu=(m_(1)m_(2))/(m_(1)+m_(2))` (Reduced mass)]
`rArr((3xx6)/(3+6))(1.8+2.2)^(2)=512x^(2)`
`rArr(2)(4)^(2)=512x^(2)`
`rArrx=(1)/(4)m=25m`