Two masses `A` and `B` connected with an inextensible string of length `l` lie on a smooth horizontal plane. `A` is given a velocity of `vm//s` along the ground perpendicular to line AB as shown in figure. Find the tension in string during their subsequent motion

Answer

`2mv^(2)//3l`

Explanation

Acceleration of mass `B=(T)/(m)`
Acceleration of mass `A=(T)/(2m)`
`therefore`Acceleration of mass `A` with repect of mass `B=a_(A)+a_(B)=(3T)/(2m)`
`thereforea_(A//B)=(v_(A//B)^(2))/(R)`
`rArr (3T)/(2m)=(v^(2))/(l)" "rArr" "T=(2mv^(2))/(3l)`