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For particles of equal masses M that mov...

For particles of equal masses M that move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

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The correct Answer is:
`sqrt((GM)/(R )((2sqrt(2)+1)/(4)))`
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BANSAL-GRAVITATION-Practice Exercise
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  4. A particle takes a time t(1) to move down a straight tunnel from the s...

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  6. The mass of earth is 80 times that of moon. Their diameters are 12800 ...

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  7. The diameter of a planet is four times that of the earth. Find the tim...

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  8. A tunnel is dug along a chord of the earth. a perpendicular distance R...

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  9. Find the height over the earth\'s surface at which the weight of a bod...

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  10. Find the kinetic energy needed to project a body of mass m from the ce...

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  13. Find the gravitational potential energy of system consisting of unifor...

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  14. Two satellites A and B of the same mass are orbiting the earth at alti...

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  15. A satellite is to revolve around the earth in a circle of radius 8000 ...

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  16. A sky laboratory of mass 2 xx 10^(3) kg has to be lifted from one circ...

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  17. A planet of mass M moves around the sun along an ellipse so that its m...

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