Home
Class 11
PHYSICS
A simple pendulam has time period T(1) w...

A simple pendulam has time period `T_(1)` when on the earth's surface and `T_(2)` when taken to a height `R` above the earth's surface where `R` is the radius of the earth. The value of `(T_(2))/(T_(1))` is-

A

1

B

`sqrt(2)`

C

4

D

2

Text Solution

Verified by Experts

The correct Answer is:
D
For a simple pendulum
`T = 2pi sqrt((l)/(g)) therefore (T_(2))/(T_(1)) = sqrt((g_(1))/(g_(2)))`
Now, `g_(1) = (GM)/(R^(2)), g_(2) = (GM)/((2R)^(2)) = (GM)/(4R^(2))`
`therefore (T_(2))/(T_(1)) =(2)/(1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    BANSAL|Exercise EXERCISE -4 Section - B|6 Videos

  • GRAVITATION

    BANSAL|Exercise EXERCISE -3 [Miscellaneous Exercise]|35 Videos

  • CENTRE OF MASS & MOMENTUM CONSERVATION

    BANSAL|Exercise EXERCISE-4 (SECTION-B) (JEE-ADVANCED Previous Year Questions)|8 Videos

  • HEAT TRANSFER

    BANSAL|Exercise Exercise|89 Videos

Similar Questions

Explore conceptually related problems

A simple pendulum has a time period T when m the earth's surface,and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. What is the value of T_2//T_1 ?

A simple pendulum has time period T when on the earth's surface and T_(2) when taken in a tunnel at depth 3R/4 along the diameter of earth, where R is the radius of earth. The value of T_(2)//T_(1)

Knowledge Check

  • A simple pendulum has a time period T_(1) when on the earth's surface and T_(2) when taken to a height R above the earth's surface, where R is the radius of the earth. The value of (T_(2))/(T_(1)) is

    A
    1
    B
    `sqrt(2)`
    C
    4
    D
    2

  • A simple pendulum has a time period T_(1) when on the earth's surface and T_(2) when taken to a height R above the earth's surface where R is the radius of the earth. The value of T_(2)//T_(1) is

    A
    1
    B
    `sqrt(2)`
    C
    4
    D
    2

  • A simple pendulum has a time taken to height R above the earth 's surface , where R is the radius of the earth .The value of (T_(2))/(T_(1)) is :

    A
    1
    B
    `sqrt(2)`
    C
    4
    D
    2

    • Similar Questions

    Explore conceptually related problems

    A simple pendulum has a time period 2 s on the earth surface. If pendulum is taken to height R/2 above the earth 's surface, (R is radius of the earth), the time period becomes

    A particle is taken to a height R above the earth's surface, where R is the radius of the earth. The acceleration due to gravity there is

    A simple pendulum has a time period T_(1) on the earth 's surface and T_(2) when taken to height 2R above the earth 's surface when R is 2R above earth 'ssurface where R is the radius of earht The value of (T_(1)// T_(2))

    A simple pendulum has a time period T_(1) on the surface of earth of radius R. When taken to a height of R above the earth's surface, its time period is T_(2) , ratio (T_(2))/(T) is

    At what height h above the earth's surface, the value of g becomes g/2 (where R is the radius of the earth)

    Home
    Profile