Two identical rods are joined at their middle points The ends are maintained at constant temperatures as indicated Find the temperature of the junction
.

Explanation

Let junction temperature be `T`
According to kirchouff's junctin law,
Net input thermal current is equal to net ouput thermal current on a junction. i.e.
`sum((DeltaQ)/(Deltat))_("in")=sum((DeltaQ)/(Deltat))_(out)`
`((100-T))/((R//2))+((75-T))/((R//2))=((T-50))/((R//2))+((T-25))/((R//2))`
`175+75=4T`
`T=62.5^(@)C`