The temperature of a body falls from `52^(@)C` to `36^(@)C` in `10` minutes when placed in a surrounding of constant temperature `20^(@)C`. What will be the temperature of the body after another `10min`. (Use Newton's law of cooling)

Explanation

To solve the problem using Newton's Law of Cooling, we will follow these steps:

### Step 1: Understand the given data
- Initial temperature of the body, \( T_1 = 52^\circ C \)
- Final temperature after 10 minutes, \( T_2 = 36^\circ C \)
- Surrounding temperature, \( T_s = 20^\circ C \)
- Time interval, \( t = 10 \) minutes

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