The rate of emission of radiation of a black body at `273^(@)C` is `E`, then the rate of emission of raidiation of this body at `0^(@)C` will be

Options

A. `(E)/(16)`
B. `(E)/(4)`
C. `(E)/(8)`
D. `0`

Explanation

To solve the problem, we will use Stefan-Boltzmann Law, which states that the power radiated by a black body is proportional to the fourth power of its absolute temperature.

### Step-by-Step Solution:

1. **Convert Celsius to Kelvin:**
- The temperature in Kelvin is given by \( T(K) = T(°C) + 273 \).
- For \( 273°C \):
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