Radius of a shere is `R` density is d and specific heat is s, Is is heated and then allowed to cool Its rate of decrease of temperature will be proportional to .

Options

A. `Rds`
B. `1//Rds`
C. `1//R^(2)ds`
D. `R^(2)ds`

Explanation

`"Radius"=R`, `"density"=d`, `"specificheat=S`
`ms(dT)/(dt)=sAT^(4)` `A=upR^(2)`
`(dT)/(dt)=(A)/(ms sigmaT^(4))` `m=dxx(4)/(3)piR^(3)`
`=(4piR^(2)sigmaT^(4))/((4)/(3)piR^(3)dxx5)`
`implies (dT)/(dt) prop (1)/(Rds)`