A metallic sphere cools from `50^(@)C` to `40^(@)C` in `300` seconds. If the room temperature is `20^(@)C` then its temperature in next `5` minutes will be -

Options

A. `38^(@)C`
B. `36^(@)C`
C. `33.3^(@)C`
D. `30^(@)C`

Explanation

To solve the problem, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature.

### Step-by-Step Solution:

1. **Identify Initial Conditions**:
- Initial temperature of the sphere, \( T_1 = 50^\circ C \)
- Final temperature of the sphere after 300 seconds, \( T_2 = 40^\circ C \)
- Room temperature (ambient temperature), \( T_a = 20^\circ C \)
...