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An ideal monoatomic gas at 300K expands ...

An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?

Text Solution

Verified by Experts

For an ideal monoatomic gas,
`gamma=5/3`
In an adiabatic process,
`TV^(gamma-1)=constant`
`therefore` `T_(f)V_(f)^(gamma-1)=T_(i)V_(i)^(gamma-1)`
or `T_(f)=T_(i)(V_(i)/V_(f))^(gamma-1)`
`=(300)(1/2)^(5/3-1)`
`=189K`
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