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vec(A)+vec(B)=2hat(i) and vec(A)- vec(B...

`vec(A)+vec(B)=2hat(i)` and `vec(A)- vec(B)=4hat(j)` then angle between `vec(A)` and `vec(B)` is ?

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To solve the problem, we need to find the angle between the vectors \(\vec{A}\) and \(\vec{B}\) given the equations: 1. \(\vec{A} + \vec{B} = 2\hat{i}\) 2. \(\vec{A} - \vec{B} = 4\hat{j}\) ### Step 1: Add the two equations We start by adding the two equations to eliminate \(\vec{B}\): \[ (\vec{A} + \vec{B}) + (\vec{A} - \vec{B}) = 2\hat{i} + 4\hat{j} \] This simplifies to: \[ 2\vec{A} = 2\hat{i} + 4\hat{j} \] ### Step 2: Solve for \(\vec{A}\) Now, divide both sides by 2: \[ \vec{A} = \hat{i} + 2\hat{j} \] ### Step 3: Substitute \(\vec{A}\) back to find \(\vec{B}\) Now, substitute \(\vec{A}\) back into one of the original equations to find \(\vec{B}\). We can use the first equation: \[ \hat{i} + 2\hat{j} + \vec{B} = 2\hat{i} \] Rearranging gives: \[ \vec{B} = 2\hat{i} - (\hat{i} + 2\hat{j}) = \hat{i} - 2\hat{j} \] ### Step 4: Calculate the dot product \(\vec{A} \cdot \vec{B}\) Now we have: \[ \vec{A} = \hat{i} + 2\hat{j} \] \[ \vec{B} = \hat{i} - 2\hat{j} \] We calculate the dot product \(\vec{A} \cdot \vec{B}\): \[ \vec{A} \cdot \vec{B} = (1)(1) + (2)(-2) = 1 - 4 = -3 \] ### Step 5: Calculate the magnitudes of \(\vec{A}\) and \(\vec{B}\) Now we find the magnitudes: \[ |\vec{A}| = \sqrt{(1)^2 + (2)^2} = \sqrt{1 + 4} = \sqrt{5} \] \[ |\vec{B}| = \sqrt{(1)^2 + (-2)^2} = \sqrt{1 + 4} = \sqrt{5} \] ### Step 6: Use the cosine formula to find the angle Using the formula for the cosine of the angle \(\theta\) between two vectors: \[ \cos \theta = \frac{\vec{A} \cdot \vec{B}}{|\vec{A}| |\vec{B}|} \] Substituting the values we found: \[ \cos \theta = \frac{-3}{\sqrt{5} \cdot \sqrt{5}} = \frac{-3}{5} \] ### Step 7: Calculate the angle \(\theta\) Now we find \(\theta\): \[ \theta = \cos^{-1}\left(-\frac{3}{5}\right) \] This gives us the angle between \(\vec{A}\) and \(\vec{B}\). The approximate value of \(\theta\) is: \[ \theta \approx 127^\circ \] ### Final Answer The angle between \(\vec{A}\) and \(\vec{B}\) is approximately \(127^\circ\). ---

To solve the problem, we need to find the angle between the vectors \(\vec{A}\) and \(\vec{B}\) given the equations: 1. \(\vec{A} + \vec{B} = 2\hat{i}\) 2. \(\vec{A} - \vec{B} = 4\hat{j}\) ### Step 1: Add the two equations We start by adding the two equations to eliminate \(\vec{B}\): ...
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BANSAL-UNIT DIMENSION, VECTOR & BASIC MATHS-EXERCISE - 3 (Miscellaneous Exercise)
  1. The two vectors A=2hat(i)+hat(j)+3hat(k) and B=7hat(i)-5hat(j)-3hat(k...

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  2. A plumber steps out of his truck, walks 60m east and 35m south and the...

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  3. Find the resultant of the three vectors shown in figure (2W1). .

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  4. If vec(a)=x(1)hat(i)+y(1)hat(j) & vec(b)=x(2)hat(i)+y(2)hat(j). The co...

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  5. A bird moves from point (1, -2) to (4, 2) . If the speed of the bird i...

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  6. vec(A)+vec(B)=2hat(i) and vec(A)- vec(B)=4hat(j) then angle between v...

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  7. Given the vectors vec(A)=2hat(i)+3hat(j)-hat(k) vec(B)=3hat(i)-2h...

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  8. A body constrained to move in y direction is subjected to a force give...

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  9. If the resultant of two forces of magnitudes P and Q acting at a point...

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  10. If the resultant of two forces of magnitudes p and 2p is perpendicular...

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  11. Given that vec(a)=vec(i)+vec(j) +vec(k), vec(b)=vec(i)-vec(j)+vec(k), ...

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  12. |vec(a)|=2,|vec(b)|=3,|vec(c)|=6 . Angle between vec(a) and vec(b),vec...

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  13. The magnitude of the vector hat(i)+xhat(j)+3hat(k) is half of the magn...

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  14. The resultant of two forces , one double the other in magnitude is pe...

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  15. Two vectors vec(A) & vec(B) are given such that angle between (vec(A)+...

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  16. Find the magnitude of the unknown forces if sum of all forces is zero.

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  17. Three boys are pulling a heavy trolley by means of 3 ropes. The boy in...

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  18. A particle is displaced from A=(2,2,4) to B=(5, -3,-1) . A constant fo...

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  19. A force vec(F)=3hat(i)+chat(j) +2hat(k) acting on a particle causes a ...

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  20. A mosquito net over a 7ftxx4 ft bed is 3 fthigh. The net has a hole at...

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