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The time period of oscillation of a simp...

The time period of oscillation of a simple pendulum is given by `T=2pisqrt(l//g)`
The length of the pendulum is measured as `1=10+-0.1` cm and the time period as `T=0.5+-0.02s`. Determine percentage error in te value of g.

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The correct Answer is:
0.09
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