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In Searle's experiment, the diameter of ...

In Searle's experiment, the diameter of the wire as measured by a screw gauge of least count `0.01cm` is `0.050cm`. The length, measured by a scale of least count `0.1cm`, is `110.0cm`. When a weight of `50N` is suspended from the wire, the extension is measure to be `0.125 cm` by a micrometer of least count `0.01cm`. Find the maximum error in the measurement of Young's modulus of the material of the wire from these data..

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The correct Answer is:
`DeltaY=0.0245Y=5.379xx10^(9)N//m^(2)`
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BANSAL-SEMICONDUCTORS-Exercise-4
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