" Find "x" if "(log_(10)(x-3))/(log_(10)(x^(2)-21))=(1)/(2)

Solve for x, (a) (log_(10)(x-3))/(log_(10)(x^(2)-21))=(1)/(2),(b)log(log x)+log(log x^(3)-2)=0; where base of log is 10 everywhere.

((log)_(10)(x-3))/((log)_(10)(x^2-21))=1/2 then find x.

Solve the following equation. (log_10(x-3))/log_(10)(x^2-21)=1/2

Solve the following equations. (viii) (log_10(x-3))/log_(10)(x^2-21)=1/2

Solve the following equations. (viii) (log_10(x-3))/log_(10)(x^2-21)=1/2

Solve the following equations. (viii) (log10(x-3))/log_(10)(x^2-21)=1/2

Find the domain of log_(10)(1-log_(10)(x^(2)-5x+16))

(log_(10)x)^(2)+log_(10)x^(2)=(log_(10)2)^(2)-1

x^(3log_(10)^(3)x)-(2)/(3)log_(10)x=100(10)^((3)/(2))

log_(10)x-(1)/(2)log_(10)(x-(1)/(2))=log_(10)(x+(1)/(2))-(1)/(2)log_(10)(x+(1)/(8))