Prove that the plane `2x+3y-4z=9` is perpendicular to each of the planes `x+2y+2z-7=0` and `5x+6y+7z=23`.

(i) Find the equation of the plane passing through (1,-1,2) and perpendicular to the planes : 2 x + 3y - 2z = 5 , x + 2y - 3z = 8 . (ii) find the equation of the plane passing through the point (1,1,-1) and perpendicular to each of the planes : x + 2y + 3z - 7 = 0 and 2x - 3y + 4z = 0 . (iii) Find the equation of the plane passing through the point (-1,-1,2) and perpendicular to the planes : 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+ 2y+3z-7=0 and 2x-3 y+4 z=0 is

Find the equation of the plane passing through the point (1,1,-1) and perpendicular to each of the planes : x+2y+3z-7=0 and 2x-3y+4z=0

Prove that the equation of the plane which is pendicular to the plane 3x+2y+6z+4=0 is 2x-6y+z=0 .

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+2y+3z=7 and 2x-3y+4z=0 l is

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+2y+3z=7 and 2x-3y+4z=0 l is

Find the vector and Cartesian equations of the plane passing through the point (1,1,-1) and perpendicular to the planes x + 2y + 3z - 7 = 0 and 2x - 3y + 4z = 0

If the planes 2x+3y-z+5=0, x+2y-kz+7=0 are perpendicular then k =

Find the equation of the plane passing through the point (1,1,-1) and perpendicular to the planes x+2y+3z-7=0 and 2x-3y+4z=0